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2015-06-01T05:46:55Z

Created page with "<span class="exam"> Solve. Provide your solution in interval notation. <math>\vert 4x + 7\vert \ge 5</math> {| class="mw-collapsible mw-collapsed" styl..."

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<span class="exam"> Solve. Provide your solution in interval notation.     <math>\vert 4x + 7\vert \ge 5</math>
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
! Foundations
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|1) What is the solution to <math>|x|\geq 3</math>?
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|2) How do you write <math>x\geq 2</math> in interval notation?
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|Answer:
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|1) The solution is <math>x\geq 3</math> or <math>x\leq -3</math>.
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|2) <math>[2,\infty)</math>
|}

Solution:

{| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
! Step 1:
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|The inequality above means <math>4x+7\geq 5</math> or <math> 4x+7\leq -5</math>.
|}

{|class = "mw-collapsible mw-collapsed" style = "text-align:left;"
! Step 2:
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|Subtracting 7 from both sides of the inequalities, we get <math>4x\geq -2</math> or <math>4x\leq -12</math>.
|}

{|class = "mw-collapsible mw-collapsed" style = "text-align:left;"
! Step 3:
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|Dividing both sides of the inequalities by 4, we have <math>x\geq -\frac{1}{2}</math> or <math>x\leq -3</math>.
|}

{|class = "mw-collapsible mw-collapsed" style = "text-align:left;"
! Step 4:
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|Using interval notation, the solution is <math>(-\infty,-3]\cup [-\frac{1}{2},\infty)</math>.
|}

{|class = "mw-collapsible mw-collapsed" style = "text-align:left;"
! Final Answer:
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|<math>(-\infty,-3]\cup [-\frac{1}{2},\infty)</math>
|}

[[004 Sample Final A|<u>'''Return to Sample Exam</u>''']]

004 Sample Final A, Problem 3 - Revision history

MathAdmin: Created page with " Solve. Provide your solution in interval notation. \vert 4x + 7\vert \ge 5 {| class="mw-collapsible mw-collapsed" styl..."

MathAdmin: Created page with " Solve. Provide your solution in interval notation. $\vert 4x + 7\vert \ge 5$ {| class="mw-collapsible mw-collapsed" styl..."