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2015-06-01T05:51:14Z

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<span class="exam"> Solve for ''x'':      <math>\log_6 \frac{1}{36} = x</math>
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!Foundations
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|How do we remove logs from an equation?
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|Answer:
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|The definition of the logarithm tells us that if <math>\log_6(x)=y</math>, then <math>6^y=x</math>.
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|
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Solution:

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! Step 1:
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|By the definition of the logarithm, <math>\log_6 \frac{1}{36} = x</math> means <math>6^x=\frac{1}{36}</math>.
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! Step 2:
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|Now, we can solve for <math>x</math>. Since <math>6^x=\frac{1}{36}</math>,
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|we must have <math>x=-2</math>.
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! Final Answer:
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| <math>x=-2</math>
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[[004 Sample Final A|<u>'''Return to Sample Exam</u>''']]

004 Sample Final A, Problem 19 - Revision history

MathAdmin: Created page with " Solve for ''x'': \log_6 \frac{1}{36} = x {| class="mw-collapsible mw-collapsed" style = "text-align:left;" !Foundatio..."

MathAdmin: Created page with " Solve for ''x'': $\log_6 \frac{1}{36} = x$ {| class="mw-collapsible mw-collapsed" style = "text-align:left;" !Foundatio..."