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	<id>https://wiki.math.ucr.edu/index.php?action=history&amp;feed=atom&amp;title=004_Sample_Final_A%2C_Problem_13</id>
	<title>004 Sample Final A, Problem 13 - Revision history</title>
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	<updated>2026-04-29T06:22:02Z</updated>
	<subtitle>Revision history for this page on the wiki</subtitle>
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	<entry>
		<id>https://wiki.math.ucr.edu/index.php?title=004_Sample_Final_A,_Problem_13&amp;diff=819&amp;oldid=prev</id>
		<title>MathAdmin: Created page with &quot;&lt;span class=&quot;exam&quot;&gt; Compute &lt;math&gt;\displaystyle{\sum_{n = 1}^6 4\left(\frac{1}{2}\right)^n}&lt;/math&gt; {| class=&quot;mw-collapsible mw-collapsed&quot; style = &quot;text-align:left;&quot; ! Foundati...&quot;</title>
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		<updated>2015-06-01T05:49:44Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;quot;&amp;lt;span class=&amp;quot;exam&amp;quot;&amp;gt; Compute &amp;lt;math&amp;gt;\displaystyle{\sum_{n = 1}^6 4\left(\frac{1}{2}\right)^n}&amp;lt;/math&amp;gt; {| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot; ! Foundati...&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;&amp;lt;span class=&amp;quot;exam&amp;quot;&amp;gt; Compute &amp;lt;math&amp;gt;\displaystyle{\sum_{n = 1}^6 4\left(\frac{1}{2}\right)^n}&amp;lt;/math&amp;gt;&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Foundations&lt;br /&gt;
|-&lt;br /&gt;
| What is the formula for the sum of the first n terms of a geometric sequence?&lt;br /&gt;
|-&lt;br /&gt;
|Answer:&lt;br /&gt;
|-&lt;br /&gt;
|The sum of the first n terms of a geometric sequence is &amp;lt;math&amp;gt; S_n=\frac{A_1(1-r^n)}{1-r}&amp;lt;/math&amp;gt; &lt;br /&gt;
|-&lt;br /&gt;
|where &amp;lt;math&amp;gt;r&amp;lt;/math&amp;gt; is the common ratio and &amp;lt;math&amp;gt;A_1&amp;lt;/math&amp;gt; is the first term of the geometric sequence.&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
{| class = &amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Step 1:&lt;br /&gt;
|-&lt;br /&gt;
|The common ratio for this geometric sequence is &amp;lt;math&amp;gt;r=\frac{1}{2}&amp;lt;/math&amp;gt;.&lt;br /&gt;
|-&lt;br /&gt;
|The first term of the geometric sequence is &amp;lt;math&amp;gt;4\frac{1}{2}=2&amp;lt;/math&amp;gt;.&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{|class = &amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Step 2:&lt;br /&gt;
|-&lt;br /&gt;
|Using the above formula, we have &lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;math&amp;gt;\displaystyle{\sum_{n = 1}^6 4\left(\frac{1}{2}\right)^n}=S_6=\frac{2(1-(\frac{1}{2})^6)}{(1-\frac{1}{2})}&amp;lt;/math&amp;gt;&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{|class = &amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Step 3:&lt;br /&gt;
|-&lt;br /&gt;
|If we simplify, we get&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;math&amp;gt;\displaystyle{\sum_{n = 1}^6 4\left(\frac{1}{2}\right)^n}=\frac{2(1-\frac{1}{64})}{\frac{1}{2}}=4\frac{63}{64}=\frac{63}{16}&amp;lt;/math&amp;gt;.&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{|class = &amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Final Answer:&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;math&amp;gt;\frac{63}{16}&amp;lt;/math&amp;gt;&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
[[004 Sample Final A|&amp;lt;u&amp;gt;'''Return to Sample Exam&amp;lt;/u&amp;gt;''']]&lt;/div&gt;</summary>
		<author><name>MathAdmin</name></author>
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