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	<id>https://wiki.math.ucr.edu/index.php?action=history&amp;feed=atom&amp;title=004_Sample_Final_A%2C_Problem_11</id>
	<title>004 Sample Final A, Problem 11 - Revision history</title>
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	<updated>2026-04-29T13:33:02Z</updated>
	<subtitle>Revision history for this page on the wiki</subtitle>
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	<entry>
		<id>https://wiki.math.ucr.edu/index.php?title=004_Sample_Final_A,_Problem_11&amp;diff=817&amp;oldid=prev</id>
		<title>MathAdmin: Created page with &quot;&lt;span class=&quot;exam&quot;&gt; Find and simplify the difference quotient &lt;math&gt;\frac{f(x + h) - f(x)}{h}&lt;/math&gt; for &lt;math&gt;f(x) = \sqrt{x - 3}&lt;/math&gt;  {| class=&quot;mw-collapsible mw-collapse...&quot;</title>
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		<updated>2015-06-01T05:49:10Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;quot;&amp;lt;span class=&amp;quot;exam&amp;quot;&amp;gt; Find and simplify the difference quotient &amp;lt;math&amp;gt;\frac{f(x + h) - f(x)}{h}&amp;lt;/math&amp;gt; for &amp;lt;math&amp;gt;f(x) = \sqrt{x - 3}&amp;lt;/math&amp;gt;  {| class=&amp;quot;mw-collapsible mw-collapse...&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;&amp;lt;span class=&amp;quot;exam&amp;quot;&amp;gt; Find and simplify the difference quotient &amp;lt;math&amp;gt;\frac{f(x + h) - f(x)}{h}&amp;lt;/math&amp;gt; for &amp;lt;math&amp;gt;f(x) = \sqrt{x - 3}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
!Foundations&lt;br /&gt;
|-&lt;br /&gt;
|1) &amp;lt;math&amp;gt; f(x+h)=?&amp;lt;/math&amp;gt;&lt;br /&gt;
|-&lt;br /&gt;
|2) How do you eliminate the &amp;lt;math&amp;gt;h&amp;lt;/math&amp;gt; in the denominator?&lt;br /&gt;
|-&lt;br /&gt;
|Answer:&lt;br /&gt;
|-&lt;br /&gt;
|1) We have &amp;lt;math&amp;gt;f(x+h)=\sqrt{x+h-3}&amp;lt;/math&amp;gt;&lt;br /&gt;
|-&lt;br /&gt;
|2) The difference quotient is &amp;lt;math&amp;gt;\frac{\sqrt{x+h-3}-\sqrt{x-3}}{h}&amp;lt;/math&amp;gt;. To eliminate the &amp;lt;math&amp;gt;h&amp;lt;/math&amp;gt; in the denominator, &lt;br /&gt;
|-&lt;br /&gt;
|you need to multiply the numerator and denominator by &amp;lt;math&amp;gt;\sqrt{x+h-3}+\sqrt{x-3}&amp;lt;/math&amp;gt; (the conjugate). &lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Step 1:&lt;br /&gt;
|-&lt;br /&gt;
|The difference quotient is &amp;lt;math&amp;gt;\frac{f(x + h) - f(x)}{h}=\frac{\sqrt{x+h-3}-\sqrt{x-3}}{h}&amp;lt;/math&amp;gt;.&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Step 2:&lt;br /&gt;
|-&lt;br /&gt;
|Multiplying the numerator and denominator by &amp;lt;math&amp;gt;\sqrt{x+h-3}+\sqrt{x-3}&amp;lt;/math&amp;gt;, we get&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;math&amp;gt;\frac{f(x + h) - f(x)}{h}=\frac{x+h-3-(x-3)}{h(\sqrt{x+h-3}+\sqrt{x-3})} &amp;lt;/math&amp;gt;&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Step 3:&lt;br /&gt;
|-&lt;br /&gt;
|Now, simplifying the numerator, we get &lt;br /&gt;
|- &lt;br /&gt;
|&amp;lt;math&amp;gt;\frac{f(x + h) - f(x)}{h}=\frac{h}{h(\sqrt{x+h-3}+\sqrt{x-3})} &amp;lt;/math&amp;gt;. Now, we can cancel the &amp;lt;math&amp;gt;h&amp;lt;/math&amp;gt; in the denominator. &lt;br /&gt;
|-&lt;br /&gt;
|Thus, &amp;lt;math&amp;gt;\frac{f(x + h) - f(x)}{h}=\frac{1}{(\sqrt{x+h-3}+\sqrt{x-3})} &amp;lt;/math&amp;gt;. &lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Final Answer:&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;math&amp;gt;\frac{f(x + h) - f(x)}{h}=\frac{1}{(\sqrt{x+h-3}+\sqrt{x-3})} &amp;lt;/math&amp;gt;&lt;br /&gt;
|}&lt;br /&gt;
[[004 Sample Final A|&amp;lt;u&amp;gt;'''Return to Sample Exam&amp;lt;/u&amp;gt;''']]&lt;/div&gt;</summary>
		<author><name>MathAdmin</name></author>
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